# How do you write a quadratic function in intercept form who has x intercepts 4, 6 and passes through points (5,-2)?

##### 1 Answer

Aug 25, 2017

#### Explanation:

#"given x-intercepts "x=b" and "x=c#

#"we can express the factors as "(x-b)" and "(x-c)#

#"and the quadratic function as the product of the factors"#

#rArry=a(x-c)(x-b)larrcolor(blue)" a is a constant"#

#"here the intercepts are "x=4" and "x=6#

#rArry=a(x-4)(x-6)#

#"to find a substitute "(5,-2)" into the equation"#

#-2=a(1)(-1)=-arArra=2#

#"the quadratic function is therefore"#

#y=2(x-4)(x-6)larrcolor(red)" in intercept form"#

graph{2(x-4)(x-6) [-10, 10, -5, 5]}