# How do you find the vertex and the intercepts for #f(x) = -3x^2 - 6x - 2#?

##### 1 Answer

Jul 19, 2016

Vertex (1, -11)

#### Explanation:

x-coordinate of the vertex:

y-coordinate of vertex:

Vertex (1, -11)

Make x = 0, y-intercept = - 2

To find x-intercepts, make y = 0 and solve the quadratic equation:

There are 2 x-intercepts (real roots):