# How do you find the vertex and the intercepts for #f(x) = -2(x+2)^2#?

##### 1 Answer

In vertex form, the vertex is given as the

The intercepts, just sub in each variable as

#### Explanation:

The equation is given to us in vertex form, making the process of determining the vertex much easier.

The base formula for vertex form is

=> Where

=> Where

=> Where

The "

Therefore, the vertex of the equation is

The intercepts can be determined by simply subbing in each of the variables as 0, and solving for the other.

First, we'll find the x-intercept. Therefore, we'll sub in the y-value as

#f(x) = -2(x+2)^2#

#y = -2(x+2)^2#

*I switched #f(x)# into #y# to make comprehension easier*

#0 = -2(x+2)^2#

#0 = (x+2)^2#

#0 = x+2#

#-2 = x#

And now the y-intercept. Therefore, we'll sub in the x-value as

#f(x) = -2(x+2)^2#

#y = -2(x+2)^2#

*I switched #f(x)# into #y# to make comprehension easier*

#= -2(0+2)^2#

#= -2(2)^2#

#= -2(4)#

#= -8#

Your parabola will look like this.

#f(x) = -2(x+2)^2# graph{-2(x+2)^2 [-10.875, 9.125, -6.28, 3.72]}

As you can see, the vertex is in fact

Hope this helps :)